Practice Question: Max Deflection at Cantilever Beam

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Solution

The maximum deflection \(\Delta_{\text{max}}\) is calculated as follows:

\[\Delta_{\text{max}} = \frac{w l^4}{8 E I}\]

 
\(w = 10 \text{ kip/ft}\)
\(l = 5 \text{ ft} \times 12 \text{ in/ft} = 60 \text{ in}\)
\(E = 29,000 \text{ ksi}\)
\(I = 200 \text{ in}^4\)

\[\Delta_{\text{max}} = \frac{10 \text{ kip/ft}\times \frac{1 \ ft}{12 \ in} \times (60\text{ in})^4}{8 \times 29,000 \text{ ksi} \times 200 \text{ in}^4} = 0.232\text{ inches}\]

 

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