% Students Correctly Answered:
66.5%
Solution
Answer: C) 0.29
Consider the relationship between saturated unit weight and water:
$$ \gamma_{sat}=\frac{\gamma_w\left(SG+e\right)}{1+e} $$
$$ Given\ \gamma_{sat}\ =\ {2\gamma}_w: $$
$$ {2\gamma}_w=\frac{\gamma_w\left(SG+e\right)}{1+e} $$
Solving for the specific gravity, SG:
$$ 2=\frac{\left(G+0.80\right)}{1+0.8};G=2.8 $$
$$ SG\ =\ 2.8 $$
Calculate water content based on its relationship with specific gravity SG and degree of saturation, S:
$$ w=\frac{S\ast e}{SG} $$
$$ where\ S=1.0\ for\ saturated\ samples $$
$$ w=\frac{1.0\ast0.8}{2.8}=0.29 $$
